Question

one of the roots of equation x^2+ mx-5 is 2 m os​

Answer 1

Answer:

p(2)=(2)^2+2m-5

0=4+2m-5

1=2m

m=1/2

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Answer 2

x² + mx - 5 = 0

Given -: Value of x is

Find -: Value of m

x² + mx -5 = 0

(2)² + m × 2 - 5 = 0

4 + 2m - 5 = 0

4 + 2m = 5

2m = 5 - 4

2m = 1

m = 1/2