One of the roots of equation x²+mx-5= 0 is 2; find m.
(A) -2
(B) -1/2
(C)1/2
(D) 2
Answers
Answered by
16
Hi ,
It is given that one root of quadratic equation
x² + mx - 5 = 0 is 2.
To find m we have to substitute m = 2 in
given equation.
Now ,
2² + m × 2 - 5 = 0
4 + 2m - 5 = 0
2m -1 = 0
2m = 1
m = 1/2
Therefore ,
Option ( C ) is correct.
I hope this helps you.
: )
It is given that one root of quadratic equation
x² + mx - 5 = 0 is 2.
To find m we have to substitute m = 2 in
given equation.
Now ,
2² + m × 2 - 5 = 0
4 + 2m - 5 = 0
2m -1 = 0
2m = 1
m = 1/2
Therefore ,
Option ( C ) is correct.
I hope this helps you.
: )
Answered by
9
Heya !!
X² + MX - 5 = 0
(2)² + M × 2 - 5 = 0
4 + 2M - 5 = 0
2M - 1 = 0
M = 1/2
Hence,
Option ( C ) is right answer.
X² + MX - 5 = 0
(2)² + M × 2 - 5 = 0
4 + 2M - 5 = 0
2M - 1 = 0
M = 1/2
Hence,
Option ( C ) is right answer.
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