Question

one of the roots of quadratic equation x^2 -3√3x+6=0 is
√2
-√3
-2√3
2√3​

Answer 1

Answer:

$2 \sqrt{3}$

Step-by-step explanation:

$x \: = \: \frac{ - b + \: \sqrt{ {b}^{2} - 4ac} }{2a} \: and \: \frac{ - b - \sqrt{ {b}^{2} - \: 4ac} }{2a} \\ = > x = \: \frac{3 \sqrt{3} + \sqrt{3 \times 3 \times 3 - 4 \times 1 \times 6} }{2 \times 1} and \: \frac{3 \sqrt{3} - \: \sqrt{3 \times 3 \times 3 - 4 \times 1 \times 6} }{2 \times 1} \\ = > x = \frac{3 \sqrt{3} + \sqrt{3} }{2} and \frac{3 \sqrt{3} - \sqrt{3} }{2} \\ = > x = 2 \sqrt{3} \:and \: \sqrt{3}$