Question

One of the roots of the equation
6x^3-4x^2-16x=0
​

Answer 1

Answer:

6x³-4x²-16x=0

2x(3x²-2x-8)=0

2x(3x²-6x+4x-8)=0

2x(3x(x-2)+4(x-2))=0

2x(3x+4)(x-2)=0

x=0 or -4/3 or 2

Answer 2

Answer:

First of all u tell me the chapter name and answer ok then I tell u ok bye

1. In two minutes u send me chapters name and answers ok