Question

One of the roots of the equation x2 +mx-5=0 is 2 find m?​

Answer 1

Step-by-step explanation:

${x}^{2} + mx - 5 = 0$

Given one of the root of the equation is 2.

$( {2)}^{2} + m \times 2 - 5 = 0$

$4 - 2m - 5 = 0$

$- 2m - 1 = 0$

$- 2m = 1$

$m = - \frac{1}{2}$