Question

One of the roots of the quadratic equation 28x² +12√6x-6=0 is. ​

Answer 1

Answer:

Formula for roots of quadratic 

expression ax2+bx+c=0 is 

=2a−b±b2−4ac

So for x2+6x−(a2+2a−8) is 

=2−6±36+4(a2+2a−8)

=2−6±9−8+a2+2a

=2−6±(a+1)2

=−3±(a+1) 

Step-by-step explanation:

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