Math, asked by gloryashes, 1 year ago

One of the roots of the quadratic equation 4mnx2 – 6m2x – 6n2x + 9mn = 0 (m, n ≠ 0) is a)-3m/2n b)3m/2n c)2m/3n d)-2m/3n

Answers

Answered by yatingarg005
2

Answer: 3m/2n

Step-by-step explanation:

4mnx2 - 6m2x - 6n2x + 9mn

2mx (2nx - 3m) - 3n(2nx-3m

(2mx-3n) (2nx-3m)

2nx-3m =0

2nx = 3m

x = 3m/2n

Answered by amitnrw
2

Given : 4mnx² -6m²x - 6n²x  + 9mn = 0

To find : Roots

Solution:

4mnx² -6m²x - 6n²x  + 9mn = 0

=> 4mnx² -6n²x - 6m²x  + 9mn = 0

=> 2nx(2mx - 3n)  - 3m(2mx - 3n) = 0

=> (2mx - 3n) (2nx - 3m) = 0

=> 2mx - 3n = 0  

=> x = 3n/2m

2nx - 3m = 0

=> x = 3m/2n

roots are 3n/2m , 3m/2n

option b) 3m/2n  is correct

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