One of the roots of the quadratic equation 4mnx2 – 6m2x – 6n2x + 9mn = 0 (m, n ≠ 0) is a)-3m/2n b)3m/2n c)2m/3n d)-2m/3n
Answers
Answered by
2
Answer: 3m/2n
Step-by-step explanation:
4mnx2 - 6m2x - 6n2x + 9mn
2mx (2nx - 3m) - 3n(2nx-3m
(2mx-3n) (2nx-3m)
2nx-3m =0
2nx = 3m
x = 3m/2n
Answered by
2
Given : 4mnx² -6m²x - 6n²x + 9mn = 0
To find : Roots
Solution:
4mnx² -6m²x - 6n²x + 9mn = 0
=> 4mnx² -6n²x - 6m²x + 9mn = 0
=> 2nx(2mx - 3n) - 3m(2mx - 3n) = 0
=> (2mx - 3n) (2nx - 3m) = 0
=> 2mx - 3n = 0
=> x = 3n/2m
2nx - 3m = 0
=> x = 3m/2n
roots are 3n/2m , 3m/2n
option b) 3m/2n is correct
Learn more:
Find out any two values of m so that the roots of x2 +mx -24 = 0 are ...
https://brainly.in/question/7533398
activity 9 finding the roots of polynomial equations find all real roots ...
https://brainly.in/question/12138040
Similar questions