Question

one of the roots of the quadratic equation x^2 - 4x + 5 = 0 is

Answer 1

Answer:

$x {}^{2} - 4x + 5 = 0$

$x {}^{2} + 1x - 5x + 5 = 0$

$x(x + 1) - 5(x + 1) = 0$

$(x - 5) \: (x + 1) = 0$

$x - 5 = 0 \: \: or \: \: x + 1 = 0$

$x = 5 \: \: or \: x = - 1$

Answer 2

$\huge\mathfrak{\bf{\underline{\underline{\purple{⍟Answer \ :}}}}}$

${x}^{2} - 4x + 5 = 0 \\ a = 1 \\ b = - 4 \\ c = 5 \\ {b}^{2} - 4ac \\ = {4}^{2} - 4(1)(5) \\ = 16 - 20 \\ = - 4 \\ by \: formula \:method \\ \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: or \: \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a } \\ = \frac{4 + \sqrt{ - 4} }{2} \: \: \: or \: \: \: \frac{4 - \sqrt{ - 4} }{2} \\ = \frac{4 + 2i}{2} \: \: \: or \: \: \: \frac{4 - 2i}{2 } \\ x = 2 + i \: \: \: \: or \: \: \: \: x = 2 - i$