One of the Saturn's moon is named as Mimas.The orbital radius of Mimas is1.87*10^8 meter from Saturn .The mean orbital period of Mimas is approximately 23 hours .Calculate the speed of Mimas with which it revolves around Saturn .Assume that the path taken is circular.
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,One of the saturn 's moon is named as mimas . the orbitradius of mimas is 1.87×10^8m from saturn. the mean orbital period of speed of mimas with which its revolves around saturn .assume that path taken is circular
One of the saturn's moon is named as - the orbital radius of minus is 1.87 into 10 raise to 8 metre from the saturn the main orbital period of minus is approximately 23 hours calculate the speed of my mess with which it revolves around the saturn assume the path taken is circular
Radius= 1.87 × 10^8
Time= 23 Hours
speed= DISTANCE/ TIME = 2∆r/ 23
= 2× 3.14× 1.87× 10^8 m/sec
23× 60×60
= 14183.09 m/sec
= 14183m/sec
Hope this helps you to gain Knowledge in Physics Speed Conce
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