Question

one of the side of rhombus is 20 cm and one of the diagonal is 24cm . Find the area of the rhombus​

Answer 1

384 cm sq

Since diagonals of rhombus bisect to each other at right angles and all sides are equal..

By using Pythagoras theorem we can calculate other diagonal...

We also know: the area of rhombus= 1/2* product of its diagonals

Answer 2

Answer:

Area of the given rhombus is $384 cm^2$

Step-by-step explanation:

Diagonals of rhombus bisect each other and are perpendicular to each other.

In the attached figure, Rhombus ABCD and its Diagonals AC and BD bisect each other at O and AC ⊥ BD.  AB = BC = CD = DA = 20 cm.  AC = 24 cm.

Area of the given rhombus is twice the Area of ΔABC formed by the given diagonal and two adjacent sides $=2 . \frac{1}{2} . OB . AC$ $=OB . 24 = 24 \sqrt{AB^2 - AO^2}$

$= 24\sqrt{20^2 - (\frac{AC}{2})^2 } cm^2 = 24\sqrt{400 - 144} cm^2 = 24\sqrt{256} cm^2 = (24).(16) cm^2$

$= 384 cm^2$