Question

one of the side of the rectangle having area x^2+9x+18sq cm is (x+3) then other side is
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Answer 1

$\pink{\boxed{GIVEN}}$

Area of Rectangle = x² + 9 x + 18  cm²

one side given (breadth) = ( x + 3 ) cm

$\pink{\boxed{ASSUMPTION}}$

Let,

the side adjacent to the given side

be k  cm (length)

$\pink{\boxed{SOLUTION}}$

area of rectangle = length × breadth

so,

x² + 9 x + 18 = (x + 3) × k

k = (x² + 9 x + 18) / (x+3)

(on dividing x² + 9 x + 18 by ( x + 3 ) we will get)

k = x + 6

Hence, the other dimension of rectangle will be ( x + 6 ) cm.

Answer 2

Area of Rectangle = x² + 9 x + 18 cm²

one side given (breadth) = ( x + 3 ) cm

Let,

the side adjacent to the given side

be k cm (length)

area of rectangle = length × breadth

so,

x² + 9 x + 18 = (x + 3) × k

k = (x² + 9 x + 18) / (x+3)

(on dividing x² + 9 x + 18 by ( x + 3 ) we will get)

k = x + 6

Hence, the other dimension of rectangle will be ( x + 6 ) cm.