Question

One of the solutions of (x^2-y^2-z^2)p+2xyq = 2xz)​

Answer 1

Answer:

5x

2

−2x+3=0

a=5,b=−2,c=3

D=b

2

−4ac

D=−56<0

So, the root are imaginary , i.e. it has two non real roots.