Question

One of the spectrum lines of caesium has a wavelength of 456nm.calculate the frequency of this line (C=3×10 raised to 18 m/s)

Answer 1

frequency =c/wavelength
=3*10raised to 18 /456*10 raised to -9=6.57*10raised to 24

Answer 2

Answer:

The frequency of the spectral line of cesium is $6.57\times 10^{14} s^{-1}$.

Explanation:

Wavelength of the spectral line$\nu = 456 nm=456\times 10^{-9} m$

Speed of the light =c = $3\times 10^8 m/s$

Frequency and wavelength are interrelated to each other by the relation:

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8 m/s}{456\times 10^{-9} m}=6.57\times 10^{14} s^{-1}$

The frequency of the spectral line of cesium is $6.57\times 10^{14} s^{-1}$.