Question

one of the two digit is 3times other.
After Interchanging the digital the
difference two number is 54.Find
the numbers.


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Answer 1

$\huge{\bf{SOLUTION:-}}$

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Let digit at one's place = x

Then digit at ten's place = 3x

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The number will be written as:-

10(3x) + x = 30x + x = 31x

After interchanging, we get:-

10(x) + 3x = 10x + 3x = 13x

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According to the question

31x - 13x = 54

18x = 54

x = $\frac{54}{18}$

x = 3

>> 3x = 3×3 = 9

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The number is

10(3x) + x = 10(9)+3 =93

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VERIFICATION

93 - 39 = 54

54 = 54

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$<marquee> Hence, the required number is 93 </marquee>$

Answer 2

Answer:

Step-by-step explanation:

Let 2digit no.=10y+x

Therefore interchanging no.=10x+y

ATQ

Case 1 x = 3y

x-3y=0 (1)

case 2 10y+x-10x-y=54

9x-9y=54

x-y=6 (2)

Solving(1)and(2)

x-3y=0

x-y= 6

x-3y=0

- x+y=-6

-2y=-6

2y=6

y = 3

put in (1)

x-3×3=0

x-9=0

x = 9