Question

One of the two digit number is three times the other digit.if you interchange the digits of this two digit number and add the resulting number to the original number ,you get 136.what is the original number

Answer 1

let ones place digit = x
let tens place digit = y
so the no. =10y + x
A.T.Q x = 3(10y) (1)
if we interchange it ,
then no. = 10x +y
therfore,.
10y +x + 10x + y = 136
11x +11y =136
x = 136- 11y
by putting this in (1)
136-11y = 30y
136 = 41y
y = 136/41
now by putting value of y in (1)
x = 30( 136/41)
x = 4080/41