Question

One of the two digit of a two digit is four times the other digit. If you interchange the digits of this two digit number and add the resulting number to the orginal number, you get 110. What is the orignal number?

Answer 1

Let ones digit be x
tens digit = 4x
Number formed = 10×4x + x = 40x+x = 41x

By interchanging digits,
ones digit = 4x
tens digit = x
New number = 10x + 4x = 14x

According to the question,

41x + 14x = 110
55x = 110
x = 110/55
x = 2

Original number = 82