one of the two digit of a two digit number is three times the other digit. If you interchange the digit of this two digit number and add the resulting number to the original number, you get 88. what is the original number?
Answers
Solution
Let the digit in tens place = x
ones place digit = 3x
ORIGINAL NUMBER = 10x + 3x = 13x
After interchanging the number
10 x 3x + x = 31x
According to the question
ORIGINAL NUMBER + NEW NUMBER = 88
13x + 31x = 88
44x = 88
x = 2
ORIGINAL NUMBER = 13x = 13 x 2 = 26
INTERCHANGING NUMBER = 31x
31 X 2 = 62
THE TWO DIGIT NUMBER OBTAIN = 62
Hence, two digit number may be:-
26 or 62
Answer:
Let one digit be x.
Let one digit be x.So, the other digit is 3x.
Let one digit be x.So, the other digit is 3x.The number formed will be
= 10×x + 3x.
10×x + 3x.=10x+3x
10×x + 3x.=10x+3x=13x.
10×x + 3x.=10x+3x=13x.After interchanging the digits we get the number as
10×3x + x
10×3x + x=30x + x
10×3x + x=30x + x=31x.
By the given condition
13x + 31x = 88
13x + 31x = 8844x = 88
13x + 31x = 8844x = 88X = 2.
13x + 31x = 8844x = 88X = 2.So, the number formed is 10×2 +3×2 = 20+6=26.
The number can also be 62.
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