Math, asked by ayushgagneja22160, 5 months ago

One of the two digits is two times the osthersdigit . If we interchanage he digits of ths

two digit number and add the resulting numberto the orginal number, we get 99. What

is the original number.​

Answers

Answered by DisneyPrincess29
3

Answer:

your question has some mistakes correct it and send again...

Answered by ashishc1403
0

Given :

One of the two digits of a two digit is two times the other digit.

We interchange the digits of this two-digit number and add the resulting number to the original number, we get 99.

To find :

The original number =?

Step-by-step explanation :

Let one digit be x.

Then, the other digit is 2x.

Then, the original number will be, 10(x + 2x) .

On simplifying 10(x + 2x) . We get,

= 10x + 3x

= 12x.

Now,

After interchanging the digits, we get,

= 10(2x + x)

= 10 × 2x + x

= 20x + x

= 21x.

Now,

After adding both numbers, we get,

➮ 12x + 21x = 99

➮ 33x = 99

➮ x = 99/33

➮ x = 3.

Therefore, We got the value of, x = 3.

Hence,

The original number,

= 10(x + 2x)

On, putting the value of x = 3 we get,

= 10(3 + 2 × 3)

= 30 + 6

= 36.

Therefore, the original number = 36.

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