Question

one of the two digits of a two digit is three times the other digit. if you interchange the digits of this two digit number and add the resulting number to the original number you get 88. what is the original number

Answer 1

Let the digit at tens place be x and the digit at units place be y.

Given that one of the two digits number is three times the other digit.

y = 3x.

Therefore the original two digit number = 10x + 3x.

After interchanging the digits:

= > 10 * 3x + x

= > 30x + x.

= > 31x.

Given that After adding the resulting number to original number, you get 88.

= > 10x + 3x + 31x = 88

= > 44x = 88

= > x = 2

Hence, the digit at tens place is 2.

Now,

The digit at units place = 3(2)

= 6.

Therefore, the original number = 26.

Hope this helps!

Answer 2

Answer:

Hey mate plzz refer to the attachment