Question

one of the two digits of a two digit no.is twice the other digit .if you interchange the digit of the two digit no.and add the resulting no. to the original no.,you get 66.what is the original no.

Answer 1

let ones digit number be x
so tens digit number = 2x
original number = x + 10*2x
= x + 20x
resulting new number= 2x + 10x
a/c to question
x+ 20x + 2x + 10x= 66
33 x = 66
x= 66/33
x=2
ones place digit is 2
so tens place digit is 4
therefore the number is 24
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