Question

One of the two digits of a two digit number is 3 times the other digit if you interchange the digits of these two digit number and add the resulting number to the original number you get 88 what is original number?

Answer 1

Hi.

Here is your answer---

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Let the Once digit in a original two digit number be y and tens digit be x.

Thus, Number =  10x + y
                        
According to the Question,
                          x = 3y ------------------------eq(i)

On Interchanging the Digits, New Number is 10y + x

Also,
      10x + y + 10y + x = 88
       11x + 11y = 88
         x + y = 8 -------------------------------eq(ii)

Putting the Value of eq(i) into eq(ii),

   3y + y = 8
       4y = 8
       y = 2.

y =2 in eq(i),

 x = 2 × 2
 x = 4

Thus, Original Two- Digits Number = 10x + y
                                                        = 10(4) + 2
                                                        = 40 + 2
                                                        = 42.

Thus, the original number is 42.

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Hope it helps.

Have a nice day.