Question

One of the two digits of a two digit number is 4 times the other number. If you interchange the digits of this two digit number and add the resulting number to the original number,you get 110. What is the original number?

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Answer 1

Answer:

Let the digit in the unit place be x. Then, tens place be 4x

so, the two digit number is 10×4x+x

with interchanging of the digits, the number will be 10 × x + 4x

According to the question,

10x + 4x + 4ox + x = 110

or, 55x = 110

or, x = 110/55

or, x = 2

Hence, the original number = 40x + x

= 40×2+2 = 80 + 2 = 82.

Answer 2

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