one of the two digits of a two digit number is three time the other digit. if you interchange the digit of this two-digit number and add the resulting number to the original number, you get 88. what is the original number?
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One of the two digits of a two digit number is three times the other digit. If you interchange the digit of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?
Let the digit at tens place be 3x
The digit at ones place be x
Original Numer = 10(3x) + x = 30x + x = 31x
Interchanged Number = 10(x) + 3x = 10x + 3x = 13x
Acording to Question
31x + 13x = 88
44x = 88
x = 88 / 44
x = 2
Therefore the numbers are 13 *2 = 26
Or 31 *2 = 62
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