Question

one of the two digits of a two digit number is three time the other digit if you interchange the digits of these two digit number and add the resulting number to original number you get 88 what is the original number​

Answer 1

${\huge{\purple{\mathbb{\bold{ANSWER}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

▪︎ Two Digit number.

▪︎ One digit is three times the other.

▪︎ Let the digit on ten's place be 10x.

▪︎ Therefore digit at ones place = 3 × x = 3x.

${\large{\blue{\bold{\underline{Therefore,}}}}}$

▪︎ The resulting number,

= 10x + 3x.

${\large{\red{\boxed{\bold{=\:13x.}}}}}$

▪︎ If we interchange digits then the resulting number,

= 3×10x + x.

= 30x + x.

${\large{\red{\boxed{\bold{=\:31x.}}}}}$

${\large{\blue{\bold{\underline{Acc\:To\:Que:-}}}}}$

=》 13x + 31x = 88.

=》 44x = 88.

=》 x = 88/44.

${\large{\green{\boxed{\bold{=》\:x\:=\:2.}}}}}$

${\large{\blue{\bold{\underline{So,}}}}}$

=》 Number at ten's place,

= 10 × x.

= 10 × 2.

${\large{\orange{\boxed{\bold{=\:20}}}}}$

=》 Number at ones place,

= 3 × x.

= 3 × 2.

${\large{\orange{\boxed{\bold{=\:6.}}}}}$

${\large{\blue{\bold{\underline{Therefore, }}}}}$

=》 Original Number,

= 20 + 6.

${\huge{\pink{\boxed{\bold{=\:26.}}}}}$

☆ Therefore the required number is 26.

{Note that number may also = 62 if we take digit at ten's place 3 times the ones place}

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