one of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two digit number and add the resulting number to the original number, you get 88.What is the original number ?
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Write the two digit number as 10x + y
:
"One of the two digits of a two digit number, is 3 times the other digit."
x = 3y
:
If u inter change the digit of this two digit number, and add the resulting
number to original number, you get 88.
(10y + x) + (10x + y) = 88
Combine like terms
11y + 11x = 88
Simplify, divide by 11
y + x = 8
We know x = 3y, therefore
y + 3y = 8
4y = 8
y = 8/4
y = 2 is the units digit
then
x = 3(2)
x = 6 is the 10's digit
:
62 if the original number
:
:
We can confirm this: 62 + 26 = 88
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