one of the two digits of a two digit number is three times the other digit. If you interchange the digit of a two digit number and add the resulting number to the original ,you get 88. what is the original number.
Answers
Answered by
31
Answer:
Let the digit in units place = x
The digit in tens place = 3x
The number is 10(3x) + x = 31x
Digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number= 10(x) + 3x = 13x
Sum of these two numbers = 88
31x + 13x = 88
44x = 88
x = 2
3x = 6
The original number is 62
Answered by
20
Answer:
let the number in ones place be x.
let the number in the tens place be 3x.
original number = 10(3x)+x
=31x
on interchanging the the digits:-
number in ones place be 3x
number in tens place be x
new number =10(x)+3x = 13x
according to the question = 13x+31x = 88
=44x = 88
x = 88/44
= 2
x = 2
3x = 3X2 = 6
3x = 6
therefore original number = 31x
= 31X2
= 62
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