Question

one of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number you get 88. What is the original number?

Answer 1

Let the unit digit = x
and tens digit = 3x
Number = x+30x = 31x
A/Q,
aftrer interchanging the digits,
Number = 3x+10x = 13x
 New Number = Number + Original Number = 88 
New Number = 13x+ 31x = 88
or,   44x = 88
or,        x = 88/44 = 2
Hence the Original Number = 31x = 31*2 = 62

Answer 2

Answer:

Step-by-step explanation:

let the number in ones place be x.

let the number in the tens place be 3x.

original number = 10(3x)+x

=31x

on interchanging the the digits:-

number in ones place be 3x

number in tens place be x

new number =10(x)+3x = 13x

according to the question = 13x+31x = 88

=44x = 88

x = 88/44

= 2

x = 2

3x = 3X2 = 6

3x = 6

therefore original number = 31x

= 31X2

= 62