Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
-original number, you get 88. What is the original number?​

Answer 1

Step-by-step explanation:

let one no be x other be 3x

ATQ

X+10(3x)

on interchanging

10(x)+3x

then

X+10(3x)-10(x)+3x=88

X+30x-10x+3x=88

31x-7x=88

24x=88

X=88/24