One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
onginal number, you get 88. What is the original number?
five.
please please tell me the answer
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Answer:
Step-by-step explanation:
Let ten's digit of a number be x
Unit digit =3x
Number = 10*x+3x
=10x+3x
=13x
Reversing the digit =31x
ATQ
New number + original number =88
=10x + 3x +31x =88
=44x = 88
x=88/44=2
Hence,2digit number =31x=31*2=62
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