One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
Answers
Answer:
The original number is 62
Step-by-step explanation:
let the one's digit of the original number be x
so, tens place digit of original number = 3x
so, value of original number = (10*3x) + x
= 30x +x
= 31x
one's digit of reverse number= 3x
tens digit of reverse number= x
value of reversed number = 10x +3x
= 13x
so, 31x + 13x = 88
44x = 88
x = 2
original number= 31x = 62
Answer:
Step-by-step explanation:
Given :-
One of the two digits of a two digit number is three times the other digit.
If you interchange the digit of this two-digit number and add the resulting number to the original number, you get 88.
To Find :-
Original Number.
Solution :-
Let the tens place digit be x.
And the ones place digit be 3x.
Number = 10x + 3x = 13x
Interchanged Number = 30x + x = 31x
According to the Question,
⇒ Number + Interchanged number = 88
⇒ 13x + 31x = 88
⇒ 44x = 88
⇒ x = 88/44
⇒ x = 2
Number = 13x = 13 × 2 = 26
The two-digit number obtained is 62.
Hence, the two-digit number be 26 or 62.
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