Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?​

Answer 1

Answer:

The original number is 62

Step-by-step explanation:

let the one's digit of the original number be x

so, tens place digit of original number = 3x

so, value of original number = (10*3x) + x

                                                 = 30x +x

                                                 = 31x

one's digit of reverse number= 3x

tens digit of reverse number= x

value of reversed number = 10x +3x

                                              = 13x

so, 31x + 13x = 88

44x = 88

x = 2

original number= 31x = 62

Answer 2

Answer:

Step-by-step explanation:

Given :-

One of the two digits of a two digit number is three times the other digit.

If you interchange the digit of this two-digit number and add the resulting number to the original number, you get 88.

To Find :-

Original Number.

Solution :-

Let the tens place digit be x.

And the ones place digit be 3x.

Number = 10x + 3x = 13x

Interchanged Number = 30x + x = 31x

According to the Question,

⇒ Number + Interchanged number = 88

⇒ 13x + 31x = 88

⇒ 44x = 88

⇒ x = 88/44

⇒ x = 2

Number = 13x = 13 × 2 = 26

The two-digit number obtained is 62.

Hence, the two-digit number be 26 or 62.

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