One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
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Let the digit in units place = x
The digit in ten's place = 3x ( Given that one digit is 3 times the other )
The number is 10(3x) + x = 30x + x = 31x
⇒ Digits are interchanged.
Digit in units place = 3x
Digit in tens place = x
The new number= 10(x) + 3x = 13x
Sum of these two numbers = 88
31x + 13x = 88
44x = 88
x = 2
3x = 6
x = 2
Original number = 31 (2) = 62
Also if u will take ten's place as x and units place as 3x your answer will be 26.
Both the answers are correct as it is given that one of the digit is three times the other. It is not specified which place of the number is three times the other.
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