Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
ANSWER:
tens digit= y [y= 3x (given)]
units digit= x
original number= 10(y) +x
new number= 10x +y (interchanged)
PLS CONTINUE THE ABOVE ANSWER AND SOLVE FOR 'x'.

Answer 1

Answer:

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Step-by-step explanation:

Let one digit be x.

So, the other digit is 3x.

The number formed will be 10×x + 3x.

=10x+3x

=13x.

After interchanging the digits,

10×3x + x

=30x + x

=31x.

After adding both numbers,

13x + 31x = 88

44x = 88

X = 2.

So, the number formed is 10×2 +3×2 = 20+6=26.

Or it can also be 62.