Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
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Answer 1

Answer:62 or 26

Step-by-step explanation: let the once digit be y and tens digit be x .

so, the no. is 10x+y

ATQ, y=3x.........(1)

and (10x+y)+(10y+x)=88

now putting the value of 1 in this equation we get,

11x+11y=88

11(x+3x)=88

4x=88/11=8

x=8/4=2

and y=3x=3*2=6

so the no. is either 62 or 26

Answer 2

Answer:

The original number is 26. And here's the explanation : - )

Step-by-step explanation:

• 6 is three times two

• 26 = digits interchange = 62

• 26 + 62 = 88

So, here you go the answer is 26. Don't forget to mark as Brainliest. Also, if you will, drop in a like, and give 5-star rating to this answer only and only and only if it helped you..................