Math, asked by ssruthi, 1 year ago

ONE OF THE TWO DIGITS OF A TWO DIGIT NUMBER IS THREE TIMES THE OTHER DIGIT.  IF YOU INTERCHANGE THE DIGITS OF THIS TWO DIGIT NUMBER AND ADD THE RESULTING NUMBER TO THE ORIGINAL NUMBER, YOU GET 88. WHAT IS THE ORIGINAL NUMBER?

Answers

Answered by VishalSharma01
486

Answer:

Step-by-step explanation:

Given :-

ne of the two digits of a two digit number is three times the other digit.

If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

To Find :-

The Number

Solution :-

Let the digits at tens place be x.

And ones place be 3x .

Original Number = 10x + 3x = 13x

Number after interchanging = 10 × 3x + x = 30x + x = 31x

According to the Question,

Original number + New number = 88

⇒ 13x + 31x = 88

⇒ 44x = 88

⇒ x = 88/44

x = 2

Original Number = 13x = 13 × 2 = 26

Therefore, by considering the tens place and ones place as 3x and x.

The two digit number obtained is 62.

Hence, the two-digit number may be 26 or 62.

Answered by poojinoone
58

Step-by-step explanation:

the above one is your answer

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