One of the two digits of a two digit number is three times the other digitpositive num
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Let the digit in units place = x
The digit in tens place = 3x
The number is 10(3x) + x = 31x
Digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number= 10(x) + 3x = 13x
Sum of these two numbers = 88
31x + 13x = 88
44x = 88
x = 2
3x = 6
The original number is 62
The digit in tens place = 3x
The number is 10(3x) + x = 31x
Digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number= 10(x) + 3x = 13x
Sum of these two numbers = 88
31x + 13x = 88
44x = 88
x = 2
3x = 6
The original number is 62
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