Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?
C
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Answer 1

Answer:

62

Steb by step explanation:

2-digit number = 10 x tens place digit + unit place digit.

$Original number = 10\times3x+x=30x+x=31x10×3x+x=30x+x=31x$

$New \: number + Original \: number = 88</p><p></p><p>\Rightarrow10x+3x+31x=88⇒10x+3x+31x=88</p><p></p><p>\Rightarrow\ 44x=88⇒ 44x=88</p><p></p><p>\Rightarrow\ x=\ \frac{88}{44}=2</p><p></p><p>$

$Hence \: , the \: 2-digit \: number = 31x=31\times2=6231x=31×2=62$

Answer 2

Now as per the given question one of the two digits of a two digit number is three times the other digit. Now the number that we took was xy and hence 26. So, option (b) is correct. And if we would have taken x = 3y then the answer that we get is 62.