Question

One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Answer 1

Answer:

62

Step-by-step explanation:

Let the unit digit= x

And tens digit = 3x

Number = x + 3x = 31x

A/Q

after interchanging the digits,

number = 3x + 10x

New number = Number + Original number = 88

New number = 13x + 31x = 88

or, 44x = 88

or, x = 88/44 = 2

Hence, the original number = 31x = 31 × 2= 62

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Answer 2

Answer is attached here.