Question

one of the two digits of a two digit number is three times the other digit if you interchange the digits of this two digit number and add the resulting number to the original number you get 88 what is the original number​

Answer 1

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Answer 2

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let the two dight number be xy

xy can be written as 10x + y

=>

According to the question

x = 3y

10y + x + 10y + x = 88

=>

11x + 11y = 88

=>

x + y = 88/11

=

x + y = 8

Now, put value of x = 3y in above equation we get

3y + y = 8

=>

4y = 8

y = 2

And

x = 6

So, the two digit number is 62