One of the two digits of a two-digit number is twice the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 33. What is the original number?
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Let the digits at tens place: x and ones place: 3x
∴ original number =10x+3x
=13x
Interchange the digits,
Digits at ones place and tens place will be x and 3x
Numbers: 10×3x+x=30x+x=31x
As per the questions
Original number + New number =88
13x+31x=88
44x=88
x=2
Original number =13x=13×2=26
Or interchanging them, we will get 62
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