Question

ONE OF THE TWO DIGITS OF A TWO DIGIT NUMBER IS TWO TIMES THE OTHER DIGIT.  IF WE INTERCHANGE THE DIGITS OF THIS TWO DIGIT NUMBER AND ADD THE RESULTING NUMBER TO THE ORIGINAL NUMBER, YOU GET 99. WHAT IS THE ORIGINAL NUMBER?​

Answer 1

Answer:

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ANSWER

Let the digit in units place be x.

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88

⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62=88.

Put 99 in the place of 88 and in 3 times