Question

one of the two digits of a two digit numberis three times the other digit if you interchange they digits of this two - digit number and add the resulting number to the original number , you get 88 . what is the original number ..... challenge you cannot answer this question ​

Answer 1

QUESTION :-

One of the two Digits of a Two-Digit Number is Three times the other Digit. If you Interchange the Digits of this Two-Digit Number & Add the resulting Number to the Original Number, you get 88. What is the Original Number?

SOLUTION :-

Let the Digit at Ten's & One's place be x and 3x respectively...

∴ The Value of the Original Number = 10 * x + 3 * x = 10x + 3x = 13x

After Interchanging the Digits,

The Value of the Resulting Number = 10 * 3x + x = 30x + x = 31x

$\Rightarrow \bold {13x + 31x = 88}\\\\\Rightarrow 44x = 88\\\\Therefore,\:\bold x = \frac{88}{44} = \bold 2$

∴ The Digit at Ten's Place = x = 2

The Digit at One's Place = 3x = 3 * 2 = 6

VERIFICATION :-

After Interchanging the Digits of the Original Number and adding the Resulting Number to the Original Number, the Sum must be 88 -

The Original Number = 26

After Interchanging the Digits, it becomes 62

Now, adding the Resulting Number to the Original Number, we get -

62 + 26 = 88

Hence, It is also Verified that the Sum is 88

CONCLUSION :-

The Original Number is 26...