Question

One of the two digits of a two digits no. is 3 times the other digit. If you interchange the digits of this two digit no. and add the resulting no. to the original no. you get 88 whatis the original no

Answer 1

Hope u like my process
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Let one of the digit of two digit numbers of ten's place be x.

So, the other digit of one's place = 3x.

So, the two digit number can be written as,
(10x + 3x) = 13x

After Interchanging,

The digit at ten's place = 3x

And the digit at one's place = x

So the new number will be = (10*3x +x)
= (30x +x) = 31 x

By problem,
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=> 13x + 31x = 88

or, 44x = 88

or, x = 88/44 = 2

So, the original number can be = (2×10 + 3×2)

= (20 +6) = 26__(answer)__

Else, the original number can be = (3×2×10 +2)

= (60 + 2) = 62.___(answer)__

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