Question

one of the two digits of a two number is three times of the other digit. if you interchange the digit of this two -digit number and add the resulting number to the original number you get 88 what is the original no?

Answer 1

62 is the original number

Answer 2

Let, the two digits are a and b.
Then, the number is (10a + b) ---- (1)
Also let, a = 3b ---- (2)
When the digits are interchanged, the number becomes (10b + a) ---- (3)
By the given condition, we add (1) no. and (3) no. expressions, which values 88.
So, (10a + b) + (10b + a) = 88.
Now, taking the help of (2) no. equation, we get
10×(3b) + b + 10b + 3b = 88
or, 44b = 88
or, b = 2
By (1) no. equation, we get
a = 3b = 3×2 = 6.
Therfore the number is {(10×6) + 2} = 62.