one of the two digits of two digit number is three times the other. if we interchange the digits and add the resulting number to the original number we get 132.find the number
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Let us assume that the number is (10x + y) and
y = 3x -- equation (1)
given that,
If we interchange the digits and add to the original number we get 132.
Hence,
(10x + y) + (10y + x) = 132
Substitute "y" value here,
10x + 3x + 10(3x) + x = 132
44x = 132
x = 132/44
x = 3
Substitute "x" value in equation (1)
y = 3x = 3(3) = 9.
Hence, the number = 10x + y
= 10(3) + 9 = 39.
(As one of the two digits is thrice than the other , It would be y = 3x or x = 3y)
Hence, the two digit number is 39 or 93.
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