One of the two digits of two digit numbers is three times the other digit. If you interchange the digits of this two - digit number and add the resulting number to the original number, you get 88. What is the original number?
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Now as per the given question one of the two digits of a two digit number is three times the other digit. Now the number that we took was xy and hence 26. So, option (b) is correct. And if we would have taken x = 3y then the answer that we get is 62.
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ANSWER = 62 , 26
- let the first number be x
given,
- the second number = 3x
general formula of 2 digit number = 10 x + y
applying here ,
two digit number = 10 (3x) + x
= 30 x + x
= 31x
interchanging , = 10 x + 3x
= 13x
13x + 31 x = 88
44x = 88
x = 88 /44
= 2
numbers = 10x + 3x
= 20 + 6
= 26
other number = 62
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