one of the two no. is 548005,the second no. is 970068 less than first. find the second no.
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Let 3rd no = 100
Then 25% less than 100 will be ((100-25)/100)*100=75
Similarly 20% less will be 80
Percent is the first number of the second=(75/80)*100=93.75%
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Long(Standard Procedure)[TYPE1]
Let 3rd no = 100
25% less means in(Percentage) 100 less is (100-25)
1 less is (100-25)/100
Therefore,in 3rd number 100 less is ((100-25)/100)*100 = 75
20% less means in(Percentage) 100 less is (100-20)
1 less is (100-20)/100
Therefore,in 3rd number 100 less is ((100-20)/100)*100 = 80
Percent is the first number of the second =>(75/80)*100=93.75%
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Long(Standard Procedure)[TYPE2]
Let 3rd no = x
25% less means in(Percentage) 100 less is (100-25)
1 less is (100-25)/100
Therefore,in 3rd number x less is ((100-25)/100)*x = 0.75x
20% less means in(Percentage) 100 less is (100-20)
1 less is (100-20)/100
Therefore,in 3rd number x less is ((100-20)/100)*x = 0.8x
Percent is the first number of the second =>(0.75x/0.8x)*100=93.75%