Question

one of the two numbers exceeds the other by 9. four times the smaller added to five times the larger gives 108.find the numbers.

Answer 1

Let the first number be x
second no. would be x+9
= 4x + 5(x+9) =108
=4x+5x+45=108
=9x+45=108
=9x= 108-45
=9x=63
=x=63/9
=x=7
thus the numbers are 7 and
x+9= 7+9 = 16

Answer 2

Let the smaller number = x.

Then the larger number exceeds the smaller by 9 = x + 9.

Given that four times, the smaller added to five times the larger gives 108.

4x + 5(x + 9) = 108

4x + 5x + 45 = 108

9x + 45 = 108

9x = 108 - 45

9x = 63

x = 63/9

x = 7

Then the larger number = 7 + 9 = 16.

Therefore the numbers are 7 and 16.


Verification:

4(7) + 5(7 + 9) = 108

28 + 5(16) = 108

28 + 80 = 108

108 = 108.


Hope this helps!