Question

One of the two numbers exceeds the other by 9. Four times the smaller added five times the larger gives 108. Find the numbers

Answer 1

Answer:

Let the smaller number be = x

Larger number = y

According to Question:-

y = x + 9

4x + 5(x + 9) = 108

4x + 5x + 45 = 108

9x + 45 = 108

9x = 108 - 45

9x = 63

x = 63/9

x = 7

Smaller number = 7

Larger number = 16

Verify:-

4(7) + 5(16) = 108

28 + 80 = 108

108 = 108

LHS = RHS

Hence, verified

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Answer 2

Answer:

let the smaller no=x

so the larger no =x+9

so 4x+5(x+9)=108

or 4x+5x+45=108

or 9x=108-45=63

or x=63/9=7

so the nos are 7 & 16(ans)

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