Question

One of the values of x in log(x+7)(36X+9) = 2 is:​

Answer 1

Answer:

yes

Step-by-step explanation:

a^m=x then m = log(a)(x) here 'a' is the base.

log(x+7)(36x+9)=2 here m=2, a = x+7, x =36x+9

(x+7)^2=36x+9

x^2-22x+44=0

when x=2 will satisfy the equation

so, 2 is the answer.

Answer 2

Answer:

By applying the logarithm rule

a^m=x then m = log(a)(x) here 'a' is the base.

We get log(x+7)(36X+9) = 2

log(a)(x)= m

So m=2

a=(x+7)

x =(36X+9)

On equating we get

a^m=x

(x+7)^2=(36X+9)

x^2 + 14x +49 =36x + 9

x^2 - 22x +40 =0

On solving we get

x^2 +(-20 -2)x + (-20.-2) =0

(x - 2) (x - 20) =0

On equating

(x - 2) =0

x =2

(x - 20) =0

x =20

Therefore the values of x are 2, 20