Question

one of the vertices of a traingle whose midpoint of edges are (3,1),(5,6),(-3,2) is:

a. (-5,-3)
b. (1,7)
c. (-11,5)
d. none​

Answer 1

Step-by-step explanation:

let the point of vertex A= ( x1,y1)

the point of vertex B= ( x2,y2)

the point of vertex C = ( x3,y3)

according to the question

$(3 \: \: 1) = (\frac{x1 + x2}{2} )( \frac{y1 + y2}{2} ) \\ \\ so \: from \: here \: on \: comparing \: both \: side \\ \\ x1 + x2 = 6$

.......... (1)

and

$y1 + y2 = 2$

.......... (2)

similarly

$x2 + x3 = 10$

............. (3)

$y2 + y3 = 12$

............ (4)

$x3 + x1 = - 6$

............. (5)

$y3 + y1 = 4$

.............. (6)

adding equation (1) (3) (5)

$2(x1 + x2 + x3) = 6 \\ (x1 + x2 + x3) = 3$

............... (7)

putting the value of (1 ) in eq (7)

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Answer 2

Answer:

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